Lab Quiz 4

A  COR = HR x SV (PPx2) = HR x {(SBP-DBP) x 2} = 59 x {(99-71)x 2}= 59 x {28 x 2}= 59 x 56 = 3304 mL/min
COE = HR x SV (PPx2) = HR x {(SBP-DBP) x 2} = 107 x {(141-92) x 2} =10486 mL/min
%D = COE-COR/COR x 100 = (10486-3304) / 3304}x 100= 217%

B  COR = HR x SV (PPx2) = HR x {(SBP-DBP) x 2} = 59 x {(99-71)x 2}= 59 x {28 x 2}= 59 x 59 = 3333 mL/min
COE = HR x SV (PPx2) = HR x {(SBP-DBP) x 2} = 107 x {(141-92) x 2} =10486 mL/min
%D = COE-COR/COR x 100 = (10486-3333) / 3333}x 100= 297%

A  5%

B  90%

C  94%

A  Just after the T wave

B  Just afer the P wave

C  Just before the QRS complex

D  Just before the P wave

A  The time of electrical activity between cardiac cycles

B  The time of electrical inactivity between ventricles

C  The time of electrical inactivity between atria

D  The time of electrical inactivity between cardiac cycles

A  SV= PP x 5  mL/beat

B  SV= PP x 2  mL/beat

A  Atrial depolarization

B  ventricle depolarization

A  stays the same

B  increase

C  decreases

D  nothing will happen

A  Time for the depolarization and repolarization of atria

B  Time for the depolarization and repolarization of ventricles

A  75 contractions / minute

B  150 contractions / minute

C  20 contractions / minutes

D  75 contractions/day

A  Decrease

B  Stay the same

C  Increase

A  Closure of the semilunar valves

B  Closure of the atrioventricular valves

C  Closure of the atrioventricular and semilunar valves

A  Smaller

B  Larger

C  Stay the same

D  Not related

A  The time required for the ventricule to depolarize

B  The time required for the heart to depolarize

C  The time required for the ventricule and the atria  to depolarize

D  The time required for atria to depolarize

A  CO=SV x HR
4870=87 x SV -> SV = 4870/87= 56 mmHg
SV=PP x 2 -> PP=56/2 =28
PP=SBP -DBP -> 28=129 – DBP -> DBP= 119 – 38 = 81 mmHg
MBP= 101 + 28/3= 110 mmHg

B  CO=SV x HR
4870=87 x SV -> SV = 4870/87= 56 mmHg
SV=PP x 2 -> PP=56/2 =28
PP=SBP -DBP -> 28=129 – DBP -> DBP= 129 – 28 = 101 mmHg
MBP= 101 + 28/3= 110 mmHg

A  4290={(20×3)x SV SV=4290/69= 71 =PPx2 => pp=71 / 2 =35.5 mmHg (36)
PP=SBP-DBP -> 35.5=131-DBP ->DBP=131-36= 95mmHg
MBP= 95+36/3= 95+12= 107 mmHg

B  4290={(20×3)x SV SV=4290/69= 71 =PPx2 => pp=71 / 2 =35.5 mmHg (36)
PP=SBP-DBP -> 35.5=131-DBP ->DBP=131-36= 95mmHg
MBP= 95+36/3= 105+12= 127 mmHg

A  15.876L/min or 16L/min

B  CO = 31.752 L