Exam 4 (2)

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Question #1

You breed a black, long-haired rabbit with a white, short-haired rabbit. All of the offspring have long, black hair. If the genes for hair color and length are closely linked on the same chromosome, what would you expect to see in the F2 generation?

A 3 black, long-haired: 9 black, short-haired: 9 white, long-haired: 1 white, short-haired

B 3 black, long-haired: 1 white, short-haired

C All long-haired black

D 15 black, long-haired: 1 black, short-haired: 1 white, long-haired: 13 white, short-haired

E 9 black, long-haired: 3 black, short-haired: 3 white, long-haired: 1 white, short-hairedite, short-haired

Question #2

A horticulturist is breeding another variety of houseplant in which two genes control leaf color. G (allele for green) is dominant to g (yellow) and B (second allele for green) is dominant to b (yellow). In this plant variety, if the two genes are homozygous recessive, then the plant is yellow. Both genes need to be dominant in order for the green color to be produced. However, if only one of these two genes is dominant, then both pigments can be produced. Two plants are crossed and a green and yellow plant is produced. Which of the genotypes listed below could apply to this green and yellow plant?

A ggBb, Ggbb

B GgBb

C ggBb, GGBb

D Ggbb

E GGBb

F GGBB

Question #3

During prometaphase, the sister chromatids organize into a single row in the center of the cell.

A TRUE

B FALSE

Question #4

Polyploidy in plants

A allows for adaptation to diverse environments.

B may alter the levels of gene expression.

C is very common.

D All of these statements are true regarding polyploidy in plants.

E allows humans to create plants with unusual flowers.

Question #5

In rabbits, spotted coat (S) is dominant to solid color (s) and black (B) is dominant to brown (b). A true-breeding black spotted rabbit is mated to a true-breeding brown solid rabbit to produce a heterozygous F1 generation. Two F1 individuals are mated, and you do not see the typical 9:3:3:1 ratio of offspring, so you take an F1 rabbit and perform a test cross. Instead of the expected ratio, you see that most progeny look like the parental rabbits but a few are new, unique phenotype. This tells you that:

A that the genes for fur pattern and fur color are epistatic

B that the genes for fur pattern (spotted vs. non-spotted) and fur color assort independently

C that the genes for fur pattern and fur color are on different chromosomes

D that fur pattern and fur color are maternally inherited

E that the genes for fur pattern and fur color are on the same chromosomes

Question #6

Imagine that fur length in a chinchilla species is a trait controlled by at least three genes. For each of these genes, short fur (PS, QS, RS) has incomplete dominance over long fur (PL, QL, or RL). A chinchilla homozygous for short fur is test-crossed with a chinchilla with long fur. What will be true of their offspring?

A 1/2 of their offspring will have long fur, 1/2 of their offspring will have short fur

B All of their offspring will have long fur

C 1/2 of their offspring will be homozygous for long fur, 1/2 of their offspring will be homozygous for short fur

D 1/4 will be homozygous for long fur, 1/4 will be homozygous for short fur, and 1/2 will be heterozygous

E All of their offspring will have intermediate-length fur

Question #7

Gregor Mendel:

A discovered the basic principles of hereditary.

B was a monk, discovered the basic principles of hereditary, carried out his experiments in an abbey garden, and carried out his experiments on heredity by doing thousands of genetic crosses on a common garden plant.

C conducted research that proved that the “blending hypothesis” was the correct explanation of how heredity worked.

D carried out his experiments in an abbey garden.

E was a monk and carried out his experiments on heredity by doing thousands of genetic crosses on a common garden plant.

F carried out his experiments on heredity by doing thousands of genetic crosses on a common garden plant.

Question #8

The H substance is needed for the proper phenotypic expression of the A, B, and AB blood types in the ABO blood typing system in humans. Individuals who are recessive for the H substance (hh) will have a type O phenotype, even if they have the A and/or B alleles. Two individuals, each with type AB blood and heterozygous at the H locus have children. What is the probability they will have a child who is phenotypically type O?

A 4/16

B 100%

C 6/16

D No chance

E 3/16

Question #9

The inheritance pattern in which the mother provides gene products to the developing egg cells is called

A maternal inheritance.

B extranuclear inheritance.

C linkage.

D X inactivation.

E genomic imprinting.

Question #10

Eyelash length is an inherited trait. In the human population, there is an eyelash length gene. There are two possible variants of this gene – an allele for long eyelashes (> 1cm) and an allele for short eyelashes (1 cm or less). How many eyelash length alleles does an individual have in one of her/his somatic cells?

A 1

B 23

C 46

D 2

E 3

Question #11

Which of the following is not a characteristic of an X-linked recessive disorder pedigree?

A More females than males are affected.

B An affected son can have normal parents.

C If a female has the trait, her father must also have it.

D The characteristic often skips a generation.

E If a woman has the characteristic, all of her sons will have it.

Question #12

Meiosis I produces ________, and meiosis II produces ________ cells.

A two diploid, two haploid

B two somatic, two gametic

C two diploid, 4 haploid

D two haploid, two haploid

E two haploid, 4 haploid

Question #13

P, D, and Q are three genes found on a single chromosome in greyhounds. The recombination frequencies between the three genes are shown below. In which order are these genes found on the greyhound chromosome? P – D = 50%; P – Q = 20%; D – Q = 30%

A P-Q-D

B D-P-Q

C It is impossible to determine.

D P-D-Q

E Q-D-P

Question #14

A gene for sweat gland production is located on the X chromosome. A man who lacks sweat glands marries a woman who has normal sweat glands. Which of the following are possible phenotypes of their children?

A Half of the girls will have sweat glands and half of the girls will lack sweat glands.

B Half of the boys will have sweat glands and half of the boys will lack sweat glands.

C The boys will be mosaic; they will have patches of skin with sweat glands and patches of skin lacking sweat glands.

D All of the boys will lack sweat glands.

E The girls will be mosaic; they will have patches of skin with sweat glands and patches of skin lacking sweat glands.

Question #15

Which of the following traits would not be considered multi-factorial?

A suicide risk

B alcoholism

C cleft lip/palate

D ABO blood type

E diabetes

Question #16

In birds, sex is determined by a ZW chromosome scheme. Males are ZZ and females are ZW. A lethal recessive allele that causes death of the embryo is sometimes present on the Z chromosome in pigeons. What would be the sex ratio in the offspring of a cross between a male that is heterozygous for the lethal allele and a normal female?

A 3:1 male to female

B 4:3 male to female

C 1:2 male to female

D 2:1 male to female

E 1:1 male to female

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